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Possible to match a NamedTuple? #95
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had a similar need and found the following work-around works nt = (; a=1, b=2)
NT = typeof(nt)
@match (; a, b) = nt begin
NT(1, b) => begin
# you have access to locals a = 1 and b = 2 here
end
end |
@xukai92 It looks like this only works for a single type of named tuple. Could be handy, but definitely not a complete solution. |
yeah but |
I had that thought as well, but I'm not sure how you would handle a case where you want to match on a named tuple that could have different types, e.g. nt = rand((
(;a=1, b=2),
(x = "x", y="z")
))
@match nt begin
(;a=1, b) => begin
@show a b
end
(;x, y) => begin
@show x y
end
end |
i guess in that case you will have to do something even more messy (deconstructing in the match statements) nts = (
(; a=1, b=2),
(; x="x", y="z"),
)
NT1, NT2 = typeof.(nts)
nt = rand(nts)
@match nt begin
NT1(1, b) => begin
(; a, b) = nt
@show a b
end
NT2(x, y) => begin
(; x, y) = nt
@show x y
end
end |
I didn't see this in the docs so I assume it's not possible. It would be really nice to be able to match NamedTuples, e.g.
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